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Short-Circuit Current Calculator

Estimate the prospective short-circuit current at the source and at a feeder point, from transformer kVA and impedance or utility fault level, with a single-phase or three-phase selection.

Source
Feeder (optional)
Set the feeder length to 0 to evaluate the fault level at the source terminals only.
Fault Current
at source (kA)
at load (kA)
Notes

About Short-Circuit Current Calculator

Before a fault exists, you must already know what it will look like. Every breaker and fuse in the panel is specified against that number - the short-circuit current that will arrive the moment something lets go.

Short-Circuit Current Calculator estimates the prospective fault current from the source (a transformer or the utility) and tracks how a feeder reduces it at the load point.

It is a study aid. Real fault studies account for motors, cables, and the exact impedance data from the network operator.

Features

  • Transformer source: kVA and %Z give terminal fault current.
  • Utility source: Enter the available short-circuit MVA.
  • Feeder effect: Length and impedance reduce the fault level.
  • 1-phase or 3-phase: Formula follows the system.
  • At source and at load: Both levels reported.
  • kA output: Directly comparable to device ratings.
  • Export: Copy or download as text, CSV or JSON.

How to Use

  1. Choose the source type (transformer or utility MVA).
  2. Enter transformer kVA and %Z or the utility fault MVA.
  3. Set the system voltage and phase.
  4. Optional: add a feeder length and impedance.
  5. Read the short-circuit current at source and at load.
  6. Compare with the device interrupting rating.

Examples

Example 1 — Transformer. 1000 kVA, 5%Z, 400 V 3-phase: 28.9 kA at the terminals.

Example 2 — Utility. 250 MVA at 11 kV: 13.1 kA; at 400 V after the transformer the level is set by the transformer impedance.

Example 3 — Feeder. A 30 m, 120 mm² run from a 28.9 kA source drops the fault to roughly 22 kA at the far end.

Benefits

  • Device ratings: Compare the kA figure with breaker ratings.
  • Source flexibility: Transformer or utility input.
  • Feeder aware: See the drop across the cable.
  • Fast and free: Instant result, no sign-up, no upload.
  • Private: Nothing is stored or logged.

Frequently Asked Questions

What is short-circuit current?
It is the current that would flow through a bolted fault at a point of the system. Equipment like breakers and fuses carry a rating - the interrupting/breaking capacity - that must exceed this value.
How is fault current found from a transformer?
Divide the transformer full-load current by the impedance expressed as a decimal. A 1000 kVA, 5%Z unit at 400 V runs about 1443 A and gives roughly 28.9 kA at its terminals.
What does %Z mean?
The percent impedance is the transformer voltage drop at full load, expressed as a percentage. A lower %Z means a stiffer source and a higher short-circuit current.
How does the feeder reduce fault current?
The impedance of the cables between the source and the fault adds in series. Longer, thinner runs pull the fault level down - the calculator shows the effect at the load point.
Single-phase vs three-phase faults?
Three-phase bolted faults give the maximum current for system design in most low-voltage networks. Single-phase (line-to-line) faults are a separate path used for specific protection studies.
Why does interrupting rating matter?
A breaker or fuse must safely clear the highest fault current it can see. If the available fault current exceeds the device rating, the device may fail to clear the fault properly.
Is my data stored?
No. Everything runs in your browser; nothing is uploaded, saved or logged.